I'm so sorry for not answer but which grade and what workbook is it?
Answer:
27π cm²
Step-by-step explanation:
step 1
Find the area of the complete circle
The area of the circle is equal to
A=πr²
we have
r=9 cm
substitute
A=π(9)²=81π cm²
step 2
Remember that the area of complete circle subtends a central angle of 360°
so
using proportion
Find the area of a sector formed by a central angle that measures 120°
81π/360°=x/120°
x=120°*81π/360°
x=27π cm²
For this case we have the following equation:
h = -16t2 + 32t + 6
Deriving we have:
h '= -32t + 32
Equaling to zero:
-32t + 32 = 0
We clear the time:
t = 32/32
t = 1 s
We are now looking for the maximum height:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
The ball reaches its maximum height in:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
option: 22 ft, 1 s
Answer:
(x-2) and (10x+7)
Step-by-step explanation:
10x²-13x-14
10x²-20x+7x-14
10x(x-2)+7(x-2)
(x-2)(10x+7)
the factors are (x-2)(10x+7)
meaning that the length and breadth are (x-2) and (10x+7)
