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3 years ago

If JK and LM are congruent and parallel, then JKL and MLK are congruent. True False

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

Answer:

TRUE

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congurent.

Hence given statement is TRUE.

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Vanessa draws one side of equilateral ΔABC on the coordinate plane at points A(–2, 1) and B(4,1). What are the possible coordina

sukhopar [10]

Answer:

Possible C:

(1 , 1 + 3sqrt(3))

(1 , 1 - 3sqrt(3))

Step-by-step explanation:

AB = 6 units

Midpoint of AB is (1,1)

C would be at x = 1

So, (1,y)

(y-1)² + (1+2)² = 6²

(y-1)² = 36 - 9

(y-1)² = 27

y - 1 = 3sqrt(3)

y - 1 = -3sqrt(3)

y = 1 + 3sqrt(3)

y = 1 - 3sqrt(3)

7 0

4 years ago

72.3 + (-39.1)

joja [24]

Answer:

72.3 - 39.1 = 4tens - 7ones + 2tenth

Step-by-step explanation:

Give the expression 72.3 + (-39.1)

opening the parenthesis:

= 72.3 + (-39.1)

= 72.3 - 39.1

Breaking the decimal values into place values

72.3 = 7tens + 2units + 3tenth

72.3 = 7(10)+2(1)+3(1/10)

72.3 =70+2+0.3

Similarly for 39.1

39.1 = 3tens + 9units + 1tenth

39.1 = 3(10)+9(1)+1(1/10)

39.1 =30+9+0.1

72.3 - 39.1 = 70+2+0.3 - (30+9+0.1)

72.3 - 39.1 = 70+2+0.3 - 30-9-0.1

72.3 - 39.1 = 70-30+2-9+0.3-0.1

72.3 - 39.1 = 40 - 7 +0.2

72.3 - 39.1 = 4tens - 7ones + 2tenth

3 0

3 years ago

Which scatterplot has a correlation coefficient closest to r = 1?

qwelly [4]

Answer:

The scatter diagram that contains the correlation coefficient closest to r = 1 is the first one shown in the attached images.

Step-by-step explanation:

The correlation coefficient "r" measures how much two variables x and y are related. When the variables are highly related, the value of r is closer to one and the points contained in the scatter diagrams are assimilated more and more to a line. When the value of r is positive the relation is crescent and therefore the slope of the line drawn by the points in the diagram has a positive slope

Therefore, to answer this question, one must search among the attached images for the dispersion diagram in which the points resemble a straight line with a positive slope.

The scatter diagram that meets the requirements mentioned is the first one that appears in the attached images

6 0

4 years ago

Read 2 more answers

Will give brainliest to correct answer.

ryzh [129]

We can solve this problem by seeing at which part both of the parts of the graphs of the function are discontinued. Both of the parts of the graph of the function are discontinued at -2, so we will have to find a function that has a value that is undefined for x = -2. We can do this using the denominator of the fraction that's in each of the functions. The function where x = -2 will cause it to be undefined is the third one, so the answer to this question is C., f (x) = $\frac{1}{x+2}$ +5.

4 0

4 years ago

Please help me it would mean a lot

emmasim [6.3K]

Answer:

44 degrees

Step-by-step explanation:

angle c = 90 degrees

angle a = 46 degrees

the measure of all sides on a triangle is 180

so to solve for the other side we can do this equation...

180 - (90 + 46) = 44

hope this helped, mark as brainliest pls

6 0

2 years ago