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Semenov [28]
3 years ago
6

Belle is walking south at an average velocity of 6 km/h. How many kilometers can she walk in three hours?

Physics
1 answer:
omeli [17]3 years ago
6 0

Answer:

I think the answer is 18 km/h

Explanation:

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distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.
a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s

So, the speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

4 0
3 years ago
in the design a thermos lab, you compared the temperature of your thermos with a container that you did not insulate. what was t
irina [24]
To see if the insulation would affect the temp of whatever you are measuring. <span />
4 0
3 years ago
Which statement is true about acceleration?
Lapatulllka [165]

Answer:

It is determined by dividing Mass by Force or newtons.

M/F = A

Explanation:

5 0
3 years ago
Which proportion can you use to find the value of a? (posted in this category because of bots)
pantera1 [17]

Answer:

But you a BjTCH

Explanation:

5 0
3 years ago
What potential difference is needed to accelerate a he+ ion (charge +e, mass 4u) from rest to a speed of 1.5×106 m/s ? e?
Nataly_w [17]

We can solve the problem by using conservation of energy.


In fact, the electric potential energy lost by the charge when moving through the potential difference is equal to the kinetic energy acquired:

\Delta U=\Delta K =K_f -K_i =K_f

where K_f is the final kinetic energy, and K_i is the initial kinetic energy, which is zero since the particle starts from rest.


We can rewrite the equation above as:

q \Delta V=\frac{1}{2}mv^2

where

q=e=1.6 \cdot 10^{-19}C is the charge of the ion

\Delta V is the potential difference

m=4u=4 (1.67 \cdot 10^{-27} kg)=6.7 \cdot 10^{-27} kg is the mass of the ion

v=1.5 \cdot 10^6 m/s is the final speed of the ion


Substituting the numbers and rearranging the equation, we can find the potential difference needed:

\Delta V=\frac{mv^2}{2q}=\frac{(6.7 \cdot 10^{-27}kg)(1.5 \cdot 10^6 m/s)^2}{2(1.6 \cdot 10^{-19}C)}=4.7 \cdot 10^4 V=47 kV


8 0
3 years ago
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