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Kipish [7]
3 years ago
15

A stone is projected from the ground with a velocity 14m/s one second later it clears a wall 2 m high. The angle of projection i

s?
Physics
2 answers:
Eva8 [605]3 years ago
6 0

Answer:

30 degrees

i can't put in my work on paper

leva [86]3 years ago
6 0

Answer:

30°

Explanation:

y = y₀ + v₀ᵧ t + ½ gt²

Given: y₀ = 0 m, v₀ = 14 m/s, and g = -9.8 m/s².

At t = 1 s, y = 2 m.

2 = 0 + (14 sin θ) (1) + ½ (-9.8) (1)²

sin θ = 6.9/14

θ ≈ 29.5°

Rounded to one sig-fig, the angle of projection is about 30° from the horizontal.

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Fluorine (F) has nine protons and ten neutrons. The atomic mass of fluorine is _____.
wel
The atomic mass is roughly equal to the sum of protons and neutrons of an atom. 
9  protons + 10 neutrons = 19
Atomic mass of Flourine is 19. 
8 0
4 years ago
A ball with a mass of 275 g is dropped from rest, hits the floor, and rebounds upward. If the ball hits the floor with a speed o
Jobisdone [24]

Answer:

-0.209 kg.m/s

Explanation:

The mass of the ball, m = 275g or 0.275 kg

Speed or velocity, v = 2.60 m/s

Momentum, P = mv

Momentum when velocity is 2.60 = 0.275 x 2.60 = 0.715 kg.m/s

Speed or velocity, v = 1.84 m/s

Momentum, P = mv

Momentum when velocity is 1.84= 0.275 x 1.84 = 0.506 kg.m/s

Change in magnitude =  0.506 - 0.715 = -0.209 kg.m/s

5 0
3 years ago
The thylacine is an extinct marsupial that once roamed Tasmania and Australia. There are several preserved specimens in existenc
grin007 [14]

Answer:

B.

Explanation:

Its just right

4 0
4 years ago
A man dropped a dime in a wishing well , he heard it 5 sec later ..Find distance traveled if moving at 10 m/s 2
Alenkasestr [34]

Answer:

The distance traveled is 109.58 m

Explanation:

The Speed of sound in air = 344 m/s

Let the time in which the dime dropped by the man reach an impact in the well = t₁

Let the time in which the sound travel from the well to the man = t₂

Then

1/2× 10 × t₁² = 344 × t₂ which gives;

5 × t₁² = 344 × t₂.........................(1)

Also the total time before the man heard the dime = t₁ + t₂ = 5

Therefore;

 t₂ = 5 - t₁

Substituting the value of t₂ in equation (1), we have;

5 × t₁² = 344 × (5 - t₁)

5·t₁² + 344·t₁ - 1720 = 0

Using the quadratic formula, we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

Which gives;

t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 5\times (-1720)}}{2\times 5}

t₁ = 4.68 s or -73.48 s

Therefore, with the positive value for t₁ = 4.68 s, we have

The distance = 1/2× 10 × 4.68² = 109.58 m

The distance traveled = 109.58 m.

8 0
4 years ago
Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
Sloan [31]

Answer:

7.55 g

Explanation:

Heat of fusion = 333kj/kg

Heat capacity, c = 4190 j/kg /k

Heat capacity in j/g /k = 0.4190

Let the Number of grams of ice that will melt = n

Number of grams * heat of fusion = heat capacity * temperature change

n * 0.333 = 0.419 * (6-0)

0.333n = 2.514

n = 2.514 / 0.333

n = 7.5495

n = 7.55 gram

Hence, the number of gram of ice that will melt is 7.55 grams

5 0
3 years ago
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