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Kipish [7]
3 years ago
15

A stone is projected from the ground with a velocity 14m/s one second later it clears a wall 2 m high. The angle of projection i

s?
Physics
2 answers:
Eva8 [605]3 years ago
6 0

Answer:

30 degrees

i can't put in my work on paper

leva [86]3 years ago
6 0

Answer:

30°

Explanation:

y = y₀ + v₀ᵧ t + ½ gt²

Given: y₀ = 0 m, v₀ = 14 m/s, and g = -9.8 m/s².

At t = 1 s, y = 2 m.

2 = 0 + (14 sin θ) (1) + ½ (-9.8) (1)²

sin θ = 6.9/14

θ ≈ 29.5°

Rounded to one sig-fig, the angle of projection is about 30° from the horizontal.

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Consider the following possibilities and select the correct choice.
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Tx not but mybe

Explanation:

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3 years ago
Can the resistors in an "unbalanced" Wheatstone bridge circuit be treated as a combination of series and/or parallel resistors?
OlgaM077 [116]

Answer:

Explanation:

The resistors in a unbalanced wheat stone bridge cannot be treated as a combination of series and parallel combination of resistors.

In case of balanced wheat stone bridge, the resistors can be treated as the combination of series and parallel combination.

Here, In the balanced wheat stone bridge

R1 and R2 be in series and Ra and Rx is series and then their combination is in parallel combination.

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4 years ago
Which of the following elements is commonly found in the Earth's crust, living matter, oceans, and atmosphere? A. carbon B. argo
jekas [21]
The answer is carbon.
8 0
3 years ago
Read 2 more answers
Which types of securities has the lowest priority in a bankruptcy proceeding?
Alex777 [14]

Answer:

Common stock

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Common stock is also regarded to as shares in which dividends are paid to the holders according to how profitable the organization is.

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4 0
3 years ago
Three identical very dense masses of 3500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,
larisa86 [58]

Answer:

<em>A) 7.37 x 10^-4 N</em>

<em>B) The resultant force will be towards the -x axis</em>

Explanation:

The three masses have mass = 3500 kg

For the force of attraction between the mass at the origin and the mass -100 cm away:

distance r = 100 cm = 1 m

gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2

Gravitational force of attraction F_{g} = \frac{Gm^{2} }{r^{2} }

where G is the gravitational constant

m is the mass of each of the masses

r is the distance apart = 1 m

substituting, we have

F_{g} = \frac{6.67*10^{-11}*3500^{2} }{1^{2} } = 8.17 x 10^-4 N

For the force of attraction between the mass at the origin and the mass 320 cm away

distance r = 320 cm = 3.2 m

F_{g} = \frac{Gm^{2} }{r^{2} }

substituting, we have

F_{g} = \frac{6.67*10^{-11}*3500^{2} }{3.2^{2} } = 7.98 x 10^-5 N

Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = <em>7.37 x 10^-4 N</em>

<em></em>

<em>B) The resultant force will be towards the -x axis</em>

7 0
3 years ago
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