The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>
To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F= 
Here we are given,
= magnetic permeability
= 4
×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F=
Or, F = 
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
Learn more about magnetic force:
brainly.com/question/2279150
#SPJ4
The kinetic energy will be greatest at the bottom of the swing motion.
The potential energy will be greatest at the highest position of the swing.
Potential energy is the energy stored in an object or system due to the position or placement of its parts. However, it is not affected by the external environment of the object or system. Kinetic energy, on the other hand, is the energy of the particles of an object or system in motion.
In an oscillating pendulum, the potential energy and gravitational kinetic energy are constantly changing. The potential and kinetic energies are maximal at extreme and intermediate positions, respectively.
Learn more about the pendulum in
brainly.com/question/14759840
#SPJ4
Plants are autotrophs
Animals are heterotrophs
Answer:
triple covalent bond
Explanation:
A triple covalent bond is formed when three pairs of electrons (six electrons) are shared between the two combining atoms. A triple bond is shown by marking three short lines between the two symbols of the atoms. It requires three more electrons to attain the stable octet.
- Hope this helps! If you need a further explanation please let me know.
Y = 42t - 16t^2
velocity = vt = dy/dt
= 42 - 32t
v(1) = 42 - 32
= 10 ft/s
Hope this helps
