In the top of the fraction its going up by one each time (1,2,3,4 so the 5 and 6 would be the top half of the fraction), and in the bottom half its also going up by one but it started at 2 so its one more than the top half (2,3,4,5, so the 6 and 7 would be the bottom half of the fraction)

4 0

3 years ago

Read 2 more answers

Can someone help me with these two questions?

fenix001 [56]

Answer:

17) A(-1,1) B(-1,4) C(5,1)

18) (From origin moving rightwards)

A(0,0) B(a, 0) C(a,a) D(0,a)

Step-by-step explanation:

17) You just count the steps, how many steps left, right, up, or down

18) The first point is at the origin, so 0,0

The second point that lies on the x axis is (a,0) as it is a distance from the origin, 0 because it's on the x-axis.

The third point is (a,a) because it is a distance to the right of the origin AND a distance upwards from the x axis.

The fourth point (0,a) because it is on the vertical line (0) and is a distance above the origin.

5 0

3 years ago

A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}$

what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

3 0

3 years ago