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Karo-lina-s [1.5K]
3 years ago
9

In certain plants, tall is dominant to short. A member of your class accidentally did not record the genotype of the parent plan

ts prior to mating them. Following the cross, you notice that the phenotypic ratio for tall to short plants is 1:1. Identify the cross that could have produced these results. Justify your reasoning

Biology
2 answers:
ella [17]3 years ago
8 0

Answer:

Heterozygous tall x homozygous short individuals

Explanation:

<em>The cross that could produce tall plant to short plant in the ratio 1:1 would be between a heterozygous tall and homozygous short individuals.</em>

Assuming the allele for tallness is represented by T and that for shortness is represented by t. TT and Tt individuals will be tall while tt individuals will be short. A cross between a heterozygous tall individual (Tt) and homozygous short individual (tt) will be such that:

Tt   x   tt

offspring: Tt (tall), Tt (tall), tt (short), and tt (short). <em>(see the attached image for the Punnet's square analysis)</em>

<em>The ratio of tall to short offspring = 1:1</em>

Hence, the cross is between heterozygous tall and homozygous short individuals.

Elena-2011 [213]3 years ago
7 0

Answer:

Heterozygous tall (Tt) and homozygous short (tt) parents

Explanation:

This question involves a single gene coding for height in a certain plant. The allele for tallness (T) is dominant over the allele for shortness (t). This means that allele 'T' will always mask the phenotypic expression of allele 't' in a heterozygous state.

According to the question, the genotypes of the parent plants that were crossed were not recorded but tall and short offsprings in a ratio 1:1 were observed. Based on this phenotypic ratio, one of the parents has to be heterozygous for the trait and the other homozygous for the recessive trait in order to produce offsprings with equal ratio of tall and short traits.

This means that the heterozygous tall parent will have a genotype: Tt, and be phenotypically tall since Tallness is dominant to shortness. The other parent which is homozygous recessive will have a genotype: tt.

In a nutshell, a cross between parents with genotypes; Tt and tt will produce four possible offsprings with two distinct genotypes i.e. Tt and tt.

Tt offsprings (2) will be phenotypically tall

tt offsprings (2) will be phenotypically short

Hence, the phenotypic ratio will be 2:2 equivalent to 1:1

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Correctly identify each of these definitions or examples as either depolarization or hyperpolarization of the plasma membrane. 1
natulia [17]

Answer:

  1. hyperpolarization
  2. depolarization
  3. hyperpolarization
  4. depolarization
  5. hyperpolarization
  6. depolarization
  7. depolarization

Explanation:

The resting membrane potential is balanced by ion leakage and ion pumping, to get an electrical signal started the membrane potential has to lose its balance. This starts with a membrane channel opening for Na+ since Na+ concentration is higher outside the cell, ions will rush into the cell. This will change the relative voltage inside the cell. The resting potential has a voltage of -70 mV, the sodium cation entering the cell cause it to become less negative. <em>This is known as depolarization.</em>

The concentration gradient for Na+ will continue to enter the cell making the voltage to become positive reaching +30 mV. At the same time, this happens, other voltage-gated channels are also opening, a concentration gradient acts on K+, as well, as it leaves the cell, it takes a positive charge with it making the membrane potential to move back to its resting voltage of -70 mV. <em>This is called repolarization. </em>

For potassium ions to reach equilibrium the membrane voltage needs to be below -70 mV, this leads to a period of <em>hyperpolarization</em> that occurs while the K+ channels are open.

I annexed an image that illustrates this action potential process.

<em>Considering the information given during depolarization there's an increase in the number of sodium leak channels (7) making the inside of the cell more positive (2) increase in the membrane potential (4), this also implies a decrease in the extracellular concentration of potassium (6)</em>

<em>Meanwhile, during hyperpolarization an increase in the extracellular concentration of potassium (3) decreases the membrane potential (1) making the inside of the cell more negative (5).</em>

I hope you find this information useful and interesting! Good luck!<em>       </em>

4 0
3 years ago
Which receptor on the helper T-cell recognizes the specific antigen from an antigen-presenting cell? Which receptor on the helpe
IgorLugansk [536]

Answer:

TCR

Explanation:

Helper T cells are the CD4T cells that are present in the inactive form. These cells have receptors for antigens on their surface. These antigen receptors are called T-cell receptors (TCRs). The function of TCR is to recognize and bind to specific foreign antigen fragments that are presented in antigen–MHC complexes. Different helper T cells have their unique TCRs to recognize a specific antigen–MHC complex. The CD4 proteins of helper T cells also interact with the MHC antigens and help maintain the TCR–MHC coupling.

5 0
3 years ago
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Anastaziya [24]
Living things go in both
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3 0
4 years ago
Which body cavity does not have a bony protection?
marusya05 [52]

Answer:

The correct answer would be C, abdominal.

Explanation:

This is true because the pelvic cavity is protected by the pelvis, the cranial cavity is protected by the skull, the spinal cavity is protected by the skull as well as the vertebral column, and the thoracic cavity is protected by the rib cage. Leaving the abdomen the only body cavity not being protected by some sort of bone.

I hope this helps! :)

4 0
4 years ago
Which statement describes many of the structures involved in the first line of defense of the immune system? They have contact w
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