Answer:
Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:
Answer:
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Explanation:
hope this helps!
We will use the formula for freezing point depression :
but first, we need to get the molality m of the solution:
- molality m = moles of C2H5OH / mass of water Kg
when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH
= 11.85 g / 46 g/mol
= 0.258 moles
and when we have the mass of water Kg = 0.368 Kg
so, by substitution on the molality formula:
∴ molality m = 0.258 moles / 0.368 Kg
= 0.7 mol/Kg
and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1
and when Kf is given = 1.86 C/m
so by substitution on ΔTf formula:
when ΔTf = i Kf m
∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg
= 1.302 °C
Answer:
Volume = 29400 cm³
Mass = 21.6 g
Explanation:
Given data:
Number of moles of water vapors = 1.2 mol
Mass of water vapor = ?
Volume of water vapors = ?
Solution:
Room temperature = 25 °C (25+273 = 298 K)
Room pressure = 1 atm
PV = nRT
V = nRT/P
V = 1.2 mol × 0.0821 atm. K⁻¹. mol⁻¹ . L × 298 K/ 1 atm
V = 29.4 L
In cm³:
29.4 × 1000 = 29400 mL
mL = cm³
Mass of water vapors:
<em>Mass = number of moles × molar mass</em>
Mass = 1.2 mol × 18 g/mol
Mass = 21.6 g
8 they have eight :))))))))
