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Artyom0805 [142]
3 years ago
9

What ordered pairs are NOT solutions to y = -5x – 4.

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

Sorry i need points to ask a question dont report pls

Step-by-step explanation:

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Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G (1,3) H (4,3) J (5,1) and K (2,1
Basile [38]

Answer: (3,2)

Step-by-step explanation: <u>Diagonal</u> is a line connecting two opposite points of a form. In parallelograms, there two diagonals and they bisect each other, i.e., the point where the diagonals meet divide them into two segments with the same measure. In short, diagonals meet at their midpoint.

The way to determine midpoint is given by

(x,y) = {\frac{x_{1}+x_{2}}{2} },\frac{y_{1}+y_{2}}{2}

(x,y) = {\frac{1+5}{2} },\frac{3+1}{2}

(x,y) = (3,2)

The coordinates where diagonals of parallelogram GHJK intersect are (3,2).

4 0
2 years ago
Solve the problem and explain the steps taken. There are four students working on a project in math class. Miguel has completed
slamgirl [31]

Answer:

10%

12.5%

13%

19%

Step-by-step explanation:

First write all of the amounts as a percent.

1/8 = 12.5%

13%

.10 = 10%

19%

Then you can order them from least to greatest.

10%, 12.5%, 13%, and then 19%

hope this helps

7 0
2 years ago
How many 1/5 liter glasses can fill with 1 1/2 liter bottle of water?
levacccp [35]

Answer:

7 glasses/bottles :)

6 0
3 years ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral:  \int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx

\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty

So it is divergent.

7 0
3 years ago
Use the properties of exponents to rewrite the expression <br> (-3yz)(-3yz)(-3yz)(-3yz)
Ipatiy [6.2K]

\bf (-3yz)(-3yz)(-3yz)(-3yz)\implies (-3yz)^1(-3yz)^1(-3yz)^1(-3yz)^1 \\\\\\ (-3yz)^{1+1+1+1}\implies (-3yz)^4\implies (-3)^4 y^4 z^4\implies 81y^4 z^4

8 0
3 years ago
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