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amm1812
3 years ago
5

____transport doesn't need an input of energy of the cell. (fill in the blank)

Biology
1 answer:
inn [45]3 years ago
7 0

Answer:

<u>Passive</u> transport

Explanation:

There are two ways molecules can get in and out of the cell. These processes are called Passive and Active transport.

Passive transport is the movement of molecules and materials from high to low concentration. No energy is needed for this process because it happens naturally.

This is in contrast to what Active transport is, where energy is needed because it moves the molecules or materials against the concentration gradient where they move from lower to higher concentration.

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What is a shared characteristic of all animals
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Regulatory proteins bind to _____. the operator the lactose-utilization genes the regulatory gene RNA polymerase transcription f
jarptica [38.1K]

Answer:

Regulatory gene

Explanation:

Transcription is one of the major processes that occurs during gene expression. It is the transfer of the genetic instructions in DNA to mRNA. A strand of mRNA is made using complementary base pairs.

However, there is need for gene expression to be regulated.

Gene regulation refers to the mechanism that acts to induce or repress the expression of a gene. These include structural & chemical changes to the genetic material, binding of proteins to specific DNA elements to regulate transcription. These proteins that influences transcription by binding to specific nucleotide sequences (DNA segments/gene) are referred to as REGULATORY PROTEINS and those involved in regulating transcription of genes are called TRANSCRIPTION FACTORS.

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5 0
2 years ago
We are studying 3 strains of bacteria, with populations p1, p2, p3, in an environment with three food sources, A, B, C. In a day
Nastasia [14]

Answer:

The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

Explanation:

From the given information:

For  food source A; we have:

3P₁ + P₂ + 2P₃ = 58    units of food A ---- (1)

For food source B; we have:

2P₁ + 4P₂ + 2P₃ = 70   units of food B  ---- (2)

For food source C; we have:

P₁ + P₂  = 20   units of food C    ----- (3)

From equation (1) and (2); we have:

3P₁ + P₂ + 2P₃ = 58

2P₁ + 4P₂ + 2P₃ = 70

By elimination method

 3P₁ + P₂ + 2P₃ = 58

-

 2P₁ + 4P₂ + 2P₃ = 70

<u>                                       </u>

<u> P₁  -   3P₂   + 0    = - 12    </u>

P₁ = -12 + 3P₂   ---- (4)

Replace, the value of P₁  in (4) into equation (3)

P₁ + P₂  = 20

-12 + 3P₂ + P₂  = 20

4P₂ = 20 + 12

4P₂ = 32

P₂ = 32/4

P₂ = 8

From equation (3) again;

P₁ + P₂  = 20

P₁ + 8 = 20

P₁  = 20 - 8

P₁  = 12

To find P₃;  replace the value of P₁ and P₂ into (1)

3P₁ + P₂ + 2P₃ = 58

3(12) + 8 + 2P₃ = 58

36 + 8 + 2P₃ = 58

2P₃ = 58 - 36 -8

2P₃ = 14

P₃ = 14/2

P₃ =  7

Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

4 0
2 years ago
Can someone help me describe these rocks pls
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6 0
2 years ago
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