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julia-pushkina [17]
3 years ago
10

There are nine different positions on a baseball team. If a team has 17 players how many different line-ups can the team make? (

Assume every player can play every position.) The team can make different line-ups. Baseball games consist of nine innings. A team wants to change its line-up every inning. If no game goes to extra innings, and a season consists of 147 games, how many complete seasons can the team play without repeating a line-up? The team can play complete seasons without repeating a line-up. (Your answer should be an integer.)
Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

A) 24310

B) 18 seasons

Step-by-step explanation:

A) We are given the team has 17 players and there are 9 different positions in the team.

This is a combination question and thus, the number of different line-ups the team can make is;

C(17, 9) = 24310

B) We are told the basketball games consists of 9 innings.

Thus,

Number of games you can fill = 24310/9 = 2701.1111

And then we are told a season consists of 147 games.

Thus;

Number of complete seasons can the team play without repeating a line-up =

2701.1111/147 ≈ 18 seasons

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Answer:

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Step-by-step explanation:

To solve this problem, we need to cross multiply. Lets input the values (1.2, 1.0, 96) as shown below:

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Next we cross multiply. We multiply 1.2 and x, and we multiply 96 and 1.0.

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96 x 1.0 = 96

Now, lets put the values above back into the equation:

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Lets solve this equation. First we divide 96 by 1.2.

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