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weqwewe [10]
3 years ago
9

If n and m are integers and n2 m2 is even, which of the following is impossible?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
The question is asking to choose among the following choices among the following choices that could be the impossible base on the said given data, in my research and further analysis, I would say that the answer would be letter D. n+m is odd. I hope you are satisfied with my answer 
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aliina [53]

Answer:

option a

Step-by-step explanation:

4 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
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saveliy_v [14]

Answer:

3rd option

Step-by-step explanation:

6 0
3 years ago
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notka56 [123]

Answer:

360 meters

Step-by-step explanation:

\sqrt{8100} = 90

one edge = 90 meters

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360 meters

4 0
3 years ago
Richard's cumulative GPA for 3 semesters_ was 2.0 for 42 credits. His fourth semester GPA was 4.0 for 14 course units. What is R
Phoenix [80]

Answer:

Richard's cumulative GPA = 2.5

Step-by-step explanation:

Richard's cumulative GPA for 3 semesters was 2.0 for 42 credits.

Average = 2

Total credits = 42

Average = sum of terms/total no of terms

2 = sum of terms/42

sum of terms = 84 ....(1)

His fourth semester GPA was 4.0 for 14 course units

Average = 4

Total credits = 14

sum of terms = 56 .....(2)

Average for 4 semesters,

A=\dfrac{84+56}{42+14}\\\\A=2.5

Hence, Richard's cumulative GPA for all 4 semesters is 2.5.

8 0
3 years ago
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