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xenn [34]
3 years ago
11

Find the perimeter of ABC with vertices A(0,-4), B(4,-4), and C(0,-1).

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
<span>you know the measure of AC that is 4 and the measure of AB that is 4. Then you do the theorem of Pythagoras 4 squared + 4 squared = hypotnuza (CB)
</span>
then + all sides
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To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ &#10;(2) \ ln \  b^{a} = a*ln \ b \\&#10;(3) \ ln \ a + ln \ b = ln \ (ab) \\&#10;(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

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5 0
3 years ago
Read 2 more answers
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3 years ago
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