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xenn [34]
3 years ago
11

Find the perimeter of ABC with vertices A(0,-4), B(4,-4), and C(0,-1).

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
<span>you know the measure of AC that is 4 and the measure of AB that is 4. Then you do the theorem of Pythagoras 4 squared + 4 squared = hypotnuza (CB)
</span>
then + all sides
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d. x = 15, y= 15√3

EXPLANATION:
This is a special triangle, more specifically a 30-60-90 degree triangle. For sake of not confusing x and y, we will use z to use as our reference for solving this triangle. The side lengths for each angle are as follows:
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