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pochemuha
3 years ago
11

What is 1 1/3 times 2 1/3

Mathematics
1 answer:
svp [43]3 years ago
6 0
3.11 is the answer for 11/3 times 2 1/3
You might be interested in
In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG?<br>A: 15<br>B: 12<br>C: 25<br>D: 30​
Ne4ueva [31]

Answer:

  • D. 30

Step-by-step explanation:

It seems J is the intersection of diagonals.

We know diagonals of the parallelogram bisect each other.

<u>It gives us:</u>

  • EG = EJ + JG and
  • EJ  = JG

<u>Substitute and solve for x:</u>

  • 6x + 3 = 10x - 5
  • 10x - 6x = 3 + 5
  • 4x = 8
  • x = 2

<u>Find the value of EJ:</u>

  • EJ = 6*2 + 3 = 15

<u>Find the value of EG:</u>

  • EG = 2*EJ = 2*15 = 30

Correct choice is D

5 0
3 years ago
Read 2 more answers
NEED HELP ASAP
iragen [17]

Answer:

2.95

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
8 - n = -4 what does N equal
Kryger [21]

Answer:

Make N alone

There is an 8 so we subtract 8 from both sides so the equation is still equal

-4 - 8 = -12

Because we are subtracting N it is positive

N = 12

8 - 12 = -4

Hope this helps

Step-by-step explanation:

8 0
4 years ago
The function f is defined as follows for the domain given.
Blizzard [7]

Answer:

range ={-6,-2,4,8}

Step-by-step explanation:

The given function is

f(x) = 2x + 2

The domain is given as:

domain = {-4,-2, 1,3}

To find the range, we plug in the domain and solve for the corresponding range value.

When x=-4,

f( - 4) =2 \times   - 4 + 2 =  - 8 + 2 =  - 6

When x=-2,

f( - 2) =2 \times   - 2+ 2 =  - 4+ 2 =  - 2

When x=1,

f( 1) =2 \times   1 + 2 =  2 + 2 = 4

When x=3,

f( 3) =2 \times  3 + 2 = 6 + 2 =  8

Therefore the range is {-6,-2,4,8}

3 0
3 years ago
Triangle ABC has vertices at A(–2, 3), B(–3, –6), and C(2, –1). Is triangle ABC a right triangle? If so, which angle is the righ
levacccp [35]

Answer:

Yes, the right angle is angle C.

Step-by-step explanation:

The given triangle has vertices at A(–2, 3), B(–3, –6), and C(2, –1).

Recall the slope formula;

m=\frac{y_2-y_1}{x_2-x_1}

The slope of the line going through AC is

m_{AC}=\frac{-1-3}{2--2}=-1

The slope of the line going through BC s

m_{AC}=\frac{-1--6}{2--3}=1

The product of the slopes of AC and BC is -1\times1=-1

This means line AC is perpendicular to BC at C.

Hence the triangle ABC is right angled at C.

6 0
3 years ago
Read 2 more answers
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