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ICE Princess25 [194]
3 years ago
12

40% of whatnumber is 32?​

Mathematics
2 answers:
Gnoma [55]3 years ago
8 0

Answer: 80%

Step-by-step explanation:

40 percent (calculated percentage %) of what number equals 32? Answer: 80.

so we have. 32 = 40% x N convert 40% to a decimal.

32 = .40 x N

divide both sides by .40. 32

/ .40 = N

= 80

Andrei [34K]3 years ago
5 0

Answer:

I think 80

Step-by-step explanation:

40% × ? = 32

? =

32 ÷ 40% =

32 ÷ (40 ÷ 100) =

(100 × 32) ÷ 40 =

3,200 ÷ 40 =

= 80

Be sure of it first

Hope this helps :)

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When 6 times a number is increased by 11 the result is 16 less than 9 times the number. Find the number.
scZoUnD [109]

Answer:

Brainly.in

Question

When <u>6</u><u> </u><u>times</u><u> </u><u>a</u><u> </u><u>number</u><u> </u> is increased by 11 the result is 16 less than 9 times the number. Find the number.

Answer · 7 votes

Answer:6x+11=9x-163x=27X=9 Please mark it brainliest

Step-by-step explanation:

Please mark it brainliest

5 0
2 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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