Answer:
The new volume will be 367mL
Explanation:
Using PV = nRT
V1 = 259mL = 0.000259L
n1 = 0.552moles
At constant temperature and pressure, the value is
P * 0.000259 = 0.552 * RT ------equation 1
= 0.552 / 0.000259
= 2131.274
V2 = ?
n2 = 0.552 + 0.232
n2 = 0.784mole
Using ideal gas equation,
PV = nRT
P * V2 = 0.784 * RT ---------- equation 2
Combining equations 1 and 2 we have;
V2 = 0.784 / 2131.274
V2 = 0.000367L
V2 = 367mL
Answer:
Explanation:
Hello!
In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:
Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:
By plugging in the moles and molarity, we obtain:
Which in mL is:
Best regards!
Answer is: mass of salt is 311,15 g.
V(H₂O) = 1,48 l · 1000 ml/l = 1480 ml.
m(H₂O) = 1480 g = 1,48 kg.
d(solution) = 1,00 g/ml.
ΔT(solution) = 13,4°C = 13,4 K.
Kf = 1,86 K·kg/mol; cryoscopic constant of water
i(NaCl) = 2; Van 't Hoff factor.
ΔT(solution) = Kf · b · i.
b(NaCl) = 13,4 K ÷ (1,86 K·kg/mol · 2).
b(NaCl) = 3,6 mol/kg.
n(NaCl) = 3,6 mol · 1,48 kg= 5,328 mol.
m(NaCl) = 5,328 mol · 58,4 g/mol = 311,15 g.
Answer:
3rd statment
Explanation:
ray 1 and 2 are same vertical line
1. A soluble salt can be prepared by reacting an acid with a suitable insoluble reactant including:
a metal
a metal oxide
a carbonate
3. I don’t know this one
4. A term base or glossary is a database containing single words or expressions related to a specific subject.
5. Strong acid is an acid that ionizes completely in aqueous solution. It always loses a proton (H+) when dissolved in water. Weak acid is an acid that ionizes partially in a solution. ... Because the rate of reaction depends upon the degree of dissociation αand strong acids have higher degrees of dissociation.
im not sure of the rest
