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Lelechka [254]
2 years ago
15

Natalia dipped two feathers in oil. Then she dipped one feather in cold water and the other feather in hot water. She swirled bo

th feathers around for 20 seconds, then removed them. Her results are in the table. Cold Water Hot Water Before Oil After Oil After Water Before Oil After Oil After Water Mass 1.2 g 4.5 g 4.2 g 1.2 g 4.4 g 3.5 g She also took a picture of each feather after swirling it in water. two feathers, each with oil and beads of water Was either the cold water or the hot water able to remove the oil? Explain your reasoning.
Chemistry
1 answer:
Alika [10]2 years ago
8 0

Answer:

The hot water was better for removing the oil.

Explanation:

You can see that because the mass went down more with the hot water. So, that means that more oil was taken out of the feather with hot water.

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Ứng dụng điều chế của lưu huỳnh thành oxit axit ?
Juli2301 [7.4K]

that's your work bro do by your own

6 0
3 years ago
Which one of the following species is diamagnetic: a. F b. Zn2+ C. Cu2+ d. Ca+​
diamong [38]

Answer:

The correct answer to this question is C

Explanation:

3 0
2 years ago
Of the colors on the visible light spectrum, which one has the longest wavelength, lowest frequency, and lowest energy?
Elenna [48]

Answer:

Red

Explanation:

Violet - shortest wavelength, around 400-420 nanometers with highest frequency. They carry the most energy.

Indigo - 420 - 440 nm

Blue - 440 - 490 nm

Green - 490 - 570 nm

Yellow - 570 - 585 nm

Orange - 585 - 620 nm

Red - longest wavelength, at around 620 - 780 nanometers with lowest frequency and least amount of energy

Therefore, <em>red </em>is the answer you're looking for.

I hope this helps and that you have a great day! :)

5 0
3 years ago
When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2

And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
Luda [366]
The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s  and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069 
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) =  16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0
3 years ago
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