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GuDViN [60]
2 years ago
15

In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compou

nd?
Chemistry
1 answer:
pishuonlain [190]2 years ago
3 0

Answer:

Succinic acid

Explanation:

The most common possibility is succinic acid

As it has decimals after whole no till hundredth it contains OH and C in most of the cases .

Let's check for succinic acid

  • C4H_6O_6
  • 4(12)+4(16)+6
  • 64+48+6
  • 118u

Yes approximately equal

Molecular formula is.

(CH_2)_2(CO_2H)_2

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Cl is highly electronegative and will actually pull away 1 electron from sodium, forming an ionic bond. 
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CuCl2+F2—>CuF2+Cl2.
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Thyroid hormone contains the mineral thyroid hormone contains the ________.
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Thyroid hormone contains the mineral iodine (option I). Details about thyroid hormone can be found below.

<h3>What is the thyroid hormone?</h3>

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8 0
1 year ago
n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains
Nitella [24]

Answer : The metal used was iron (the specific heat capacity is 0.449J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of unknown metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of unknown metal = 150 g

m_2 = mass of water = 200 g

T_f = final temperature of water = 34.3^oC

T_1 = initial temperature of unknown metal = 150.0^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC

c_1=0.449J/g^oC

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is 0.449J/g^oC).

6 0
3 years ago
A 13.1-g sample of CaCl2 is dissolved in 104 g of water, with both substances at 24.7°C. Calculate the final temperature of the
likoan [24]

Answer:

The final temperature of the solution is 44.8 °C

Explanation:

assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:

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Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C)  is q dis= -83.3 KJ/mol . And the molecular weight is

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Q dis = q dis * n  = q dis * m/M =  -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ

Qdis= -9.84 KJ

Also Qsol = ms * Cs * (T - Ti)

therefore

ms * Cs * (T - Ti) + Qdis = 0

T=  Ti - Qdis * (ms * Cs )^-1   =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ

T= 44.8 °C

7 0
3 years ago
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