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GuDViN [60]
2 years ago
15

In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compou

nd?
Chemistry
1 answer:
pishuonlain [190]2 years ago
3 0

Answer:

Succinic acid

Explanation:

The most common possibility is succinic acid

As it has decimals after whole no till hundredth it contains OH and C in most of the cases .

Let's check for succinic acid

  • C4H_6O_6
  • 4(12)+4(16)+6
  • 64+48+6
  • 118u

Yes approximately equal

Molecular formula is.

(CH_2)_2(CO_2H)_2

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6 0
1 year ago
Review the PCR (Calvin-Benson-Basham) cycle and the photochemical (light) reactions. If photosynthesizing green algae are provid
stepladder [879]

Answer:

Explanation:

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7 0
3 years ago
How many grams of CO2 evolved from a 1.205g sample that is 36% MgCO3 and 44% K2CO3 by mass?
emmasim [6.3K]

Mass of CO₂ evolved : 0.108 g

<h3>Further explanation</h3>

Given

1.205g sample, 36% MgCO3 and 44% K2CO3

Required

mass of CO2

Solution

  • mass of MgCO₃ :

0.36 x 1.205 g=0.4338 g

mass C in MgCO₃(MW MgCO₃=84 g/mol,  Ar C = 12/gmol)

= (12/84) x 0.4338

= 0.062 g

  • mass of K₂CO₃ :

0.44 x 1.205 g = 0.5302 g

Mass C in K₂CO₃(MW=138 g/mol) :

= (12/138) x 0.5302

= 0.046 g

Total mass Of CO₂ :

= 0.062 + 0.046

= 0.108 g

7 0
3 years ago
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