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Norma-Jean [14]
3 years ago
14

Identify the family to which the compound (h3c−ch2oh) belongs. identify the family to which the compound (a) belongs. alcohol et

her aldehyde ketone carboxylic acid ester amine
Chemistry
2 answers:
ycow [4]3 years ago
6 0

Answer:

The compound  CH_{3}CH_{2}OH belongs to the alcohol family

Explanation:

The given compound, CH_{3}CH_{2}OH is a derivative of the alkane ethane CH_{3}CH_{3} in which one of the H atoms is replaced by an -OH group.

When a hydroxyl (OH) group is attached to an alkyl group (R) the compound formed is an alcohol represented by the general formula ROH. The given compound  CH_{3}CH_{2}OH is ethanol.

OLga [1]3 years ago
5 0
Each of the organic compounds mentioned has a general formula so that we can identify the classification of a certain substance. The compound CH₃CH₂OH is an alcohol because it follows the general formula R-OH, where R is a hydrocarbon chain. In this case, the hydrocarbon chain is ethane. When a hydroxyl functional group is attached, it becomes an alcohol whose name is ethanol.
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3 Apply Use context clues to write your own definitions for the words definite and occupy.
motikmotik

Answer:

Explanation:

own definitions for the words definite and occupy.

Example sentence

Solid is the state of matter that has a definite shape and volume.

definite:

__________

Example sentence

A larger container will allow a gas to occupy more space.

occupy:

3 0
2 years ago
When 0.25 moles of NH3 are produced according to the reaction below, how many moles of H2 must have reacted?
marissa [1.9K]

Answer:

Explanation:

by stoichiometry

nNH3/2=nH2/3

0.25/2=nH2/3

nH2=0.25×3/2

nH2=0.375 mol

so its 0.38 mol

6 0
3 years ago
Read 2 more answers
A mixture containing 20 mole % butane, 35 mole % pentane and rest
notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB

Whereas y accounts for the fractions at the outlet distillate and x for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

0.9=\frac{y_bD}{z_bF}

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

y_bD=0.9*z_bF=0.9*0.2*100mol=18mol

The total distillate flow:

y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol

And the total bottoms flow:

F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025

Then, the molar fraction of pentane and hexane:

x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422

x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

8 0
3 years ago
Read 2 more answers
PLz help ASAP
Andrews [41]
  1. it is at the bottom trust me i did the test
6 0
3 years ago
Read 2 more answers
Which of the following chemical formulas show three molecules of a compound that has one
mr_godi [17]

The chemical formula : 3HgBr₂(Mercury(II) bromide)

<h3>Further explanation</h3>

Given

The chemical formulas of Mercury and Bromine

Required

The appropriate chemical formula

Solution

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

The number of molecules is determined by the coefficient in front of the compound

the number of atoms is determined by the subscript after the atom and the coefficient

Three molecules⇒ coefficient = 3

one atom of Mercury ⇒Hg

two atoms of Bromine ⇒ Br₂

The chemical formula : 3HgBr₂

6 0
3 years ago
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