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Vinvika [58]
3 years ago
15

What's the conversion factor used to convert inches to yards

Mathematics
1 answer:
igomit [66]3 years ago
7 0
12in/1foot and 3feet/yard

or 12in = 1foot
3feet= 2Yard
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Find the derivative of f(x)=4x+7 at x=5
Marizza181 [45]
The answer is 27??????

5 0
3 years ago
Read 2 more answers
HELPPP ASAP PLEASE FOR BRAINLEST
Rasek [7]

Answer:

D

Step-by-step explanation:

A system of linear equations has infinite solutions when the graphs are the exact same line.

Therefore, the answer is D

7 0
2 years ago
why do whole numbers raised to an exponent get greater while fractions raised to an exponent get smaller?
Scrat [10]
Because 3^2 = 9
When you do (⅓)^2 what you are really doing is
(1^2)/(3^2) = 1/9


If you have (⅔)^2 you do
(2^2)/(3^2) = 4/9

Fractions get smaller because the denominator is also being squared which makes the denominator get bigger and when the denominator is bigger, you are dividing by a larger number which gives you a smaller answer. Whereas when you raise a whole number to an exponent, only the numerator get bigger because the denominator is 1 and 1 raised to any exponent is still 1

3^2 = (3^2)/(1^2) = 9/1 = 9
6 0
3 years ago
Find the value of the coefficient of
Korolek [52]
The solution to the problem is as follows:
<span>
the genaral term is 5Cr(-1)^r 2^r x^(5-2r) 
and so need 5-2r = -1 => r = 3 
Coeff is then 5C3 (-1)^3 2^3 = -80
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
7 0
4 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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