You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
Solution Step1 Converting 112 to base 10.
1*82=64
1*81=8
2*80=2
Adding all to get Ans=7410 <span>Step2 converting 7410 to 2</span> The equation calculation formula for 7410 number to 2 is like this below.
2|74
2|37|0
2|18|1
2|9|0
2|4|1
2|2|0
2|1|0
2|1|1
<span>Ans:10010102</span>
Answer:
11 * I
Unless you can tell me what I is equal to, I can't give you a number as an answer. Just take what ever I is equal to, an multiply it by 11. If the answer choices are equations rather than numbers, than just say 11 * 1.
If the question comes with any more information, please comment so I can give you a stronger answer.
Hope this helps! :)
-Sophia
Answer:
4/1. with an intercept of 5
