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Evgen [1.6K]
3 years ago
15

The price of blackberries at a farm is $1.56 per pound. Which equation can be used to determine c, the total price of n pounds o

f blackberries?
c = 1.56n
c equals 1.56 over n
c = 1.56 + n
c = 1.56 − n
Mathematics
1 answer:
saveliy_v [14]3 years ago
3 0
C=1.56n

Should give the the total price of n pounds of blackberry
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Don Trastmi is a respected investment consultant, but with a bit of a pessimistic attitude. He always projects correctly when th
Mrrafil [7]

Answer:

The answer is "\bold{\frac{6}{10}}"

Step-by-step explanation:

\to p(\frac{\text{Market is falling}}{\text{The expected demand is fall Don}}) =1\\\\\to p(\frac{\text{Market is falling}}{\text{The expected demand is rising Don}}) =0.6

That's why the answer is \to \frac{6}{10}

3 0
3 years ago
Robert slices a large loaf of bread to make 12 sandwiches. He made 3 turkey sandwiches and 5 veggie sandwiches. The rest are ham
lions [1.4K]
We already know that there are 12 sandwiches.

If there are 3 turkey and 5 veggie then there's 8 out of 12 sandwiches that aren't ham.

12 sandwiches - 8 non-ham sandwiches = 4 ham sandwiches

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We need to simplify this now.
4/12 can be divided by 4

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3 0
3 years ago
The number -3 can be classified as which of the following?
sp2606 [1]

<u>Answer</u>:

-3 is an integer, rational number and real number , so correct option id D) that is all of the above.

<u>Explanation:</u>

Integer is all natural number  that a 1 , 2 , 3 , 4 ……. And zero and negative of natural numbers like -1 , -2 , -3 , - 4 ……. So -3 is an integer.

Rational number is the number which can be represented in the form of p/q where p and q are integers and q ≠ 0 . As -3 can be represented as (-3)/1 . hence -3 is also a rational number.

Real number is all number which can be represented on number line. All integers and rational numbers are real numbers . so -3 is also a real number.

Hence as -3 is an integer, rational number and real number , so correct option id D) that is all of the above.

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3 years ago
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romanna [79]
Answer is:
Hope this helps

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3 years ago
Simplify 3[2^3 + (4-2)^3 - (6-2)^2]
Ivahew [28]

Answer:

\boxed{0}

.

Step-by-step explanation:

3(2^3 + (4 - 2)^3 - (6 - 2)^2)

= 3(2^3 + 2^3 - 4^2)

= 3(2.2^3 - (2^2)^2)

= 3(2^4 - 2^4)

= 3(0)

= 0

6 0
3 years ago
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