Using the identity:
, we get:
There are two solutions to this equation:
1) 
Since the period of cosine is 2π, so 0 + 2π = 2π will also be a solution to the given equation
2) 
Therefore, there are 3 solutions to the given trigonometric equation.
Answer:
the answer would be b my friend
Step-by-step explanation:
Ok here is what I think.
Let us first number these statements, as #1, and #2.
First statement: 3x + 8y = 12 (1)
Second Statement: 2x + 2y = 3 (2)
Now, we can work from this.
We want to make one of the equations be equal to 0 so that at the end when we check they can be equal to each other.
Let us use 4.
3x+8y=12 1-8x-8y=-12 2
This gives us:-5x = 0
Now we should try and isolate x so we can substitute it into one of the equations.
We have -5x=0
and x=0
3(0)+8y=12
8y=12
y=12/8
y=3/2
Plug in these new equations
y=3/2 and y=0 into any of the first equations
3x+8y=12 3(0)+8(3/2)= 12 8(3/2)=12 4(3)=12 12=12
Now we know it works, thats our check^^
Answer:
y = -3/4x + 4
Step-by-step explanation:
y = mx + b
-2 = (-3/4)(8) + b
-2 = -6 + b
4 = b
y = -3/4x + 4
