All categories

3 years ago

I need help with this

Mathematics

1 answer:

german3 years ago

4 0

Answer:

Climate to Support systems, tectonic to changes constantly, perceptions to water falling, Solar to interactions, ecosystem to very large scale.

Step-by-step explanation:

Have a nice day! :D

You might be interested in

On Jiamin's trip to Wisconsin, her average rate of speed for the whole 5-hour trip was 62 miles per hour. For the first two hour

GaryK [48]

Average speed for the entire journey was 62 miles per hour.
Total time of the journey was 5 hours.

In first 2 hours, her average speed was 60 miles per hour. This means, she covered 120 miles in first two hours, as

Distance = Speed x Time

The total distance of the entire journey was:

Total Distance = 62 x 5 =310 miles

Out of these 310 miles, she covered 120 miles in first two hours. So this means she covered (310 - 120) miles in next 3 hours.

Thus she covered 190 miles in 3 hours. So her average speed will be 190/3 miles per hour which is equal to 63.33 miles per hour.

So, the average speed for last 3 hours of the trip was 63.33 miles per hour

5 0

3 years ago

5. Which equation does not represent a line

Dimas [21]

D because the x-intercept would be 1/3, not 3

7 0

3 years ago

Turn this sentence into an equation.

pochemuha

The answer for this problem is 22=2g

6 0

3 years ago

Water is flowing into a 50-gallon bathtub at a rate of 2.3 gallons per minute (gpm). To the nearest minute, how long will it tak

Contact [7]

It would be b. If you divide the 2

4 0

3 years ago

For each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts. A large shipmen

Stella [2.4K]

Answer:

(a) The p-value of the test statistic should be 0.33.

(b) No, there is not sufficient evidence to reject the entire shipment.

Step-by-step explanation:

We are given that for each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts.

A quality control manager randomly selects 50 of the parts from the shipment and finds that 6 parts are defective.

Let p = proportion of defective parts among the current shipment.

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the defective parts in the shipment is at most 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the defective parts in the shipment is greater 10%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of parts that are defective among the current shipment = $\frac{6}{50}$ = 12%

n = sample of parts from the shipment = 50

So, test statistics = $\frac{0.12-0.10}{\sqrt{\frac{0.12(1-0.12)}{50} } }$

= 0.44

The value of z test statistics is 0.44.

(a) Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.44) = 1 - P(Z $\leq$ 0.44)

= 1 - 0.67003 = 0.3299 ≈ 0.33

(b) Since, the P-value of test statistics is more than the level of significance as 0.33 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the defective parts in the shipment is at most 10%.

4 0

3 years ago