1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anuta_ua [19.1K]
3 years ago
15

Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

Mathematics
1 answer:
VikaD [51]3 years ago
3 0
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
You might be interested in
Skate World offers birthday parties for a fee of $130 plus $3 per person. If you can spend no more than $190 on your party, what
tankabanditka [31]
The max amount of ppl is 20
7 0
3 years ago
Two different plants grow each year at different rates, which are represented by the functions f(x) = 4x and g(x) = 5x + 2. What
Salsk061 [2.6K]

I believe you answer would be D

8 0
3 years ago
Read 2 more answers
What fraction of 42 g is 7000 mg​
Vsevolod [243]

Answer:

3/500

Step-by-step explanation:

42/7000 simplified is 3/500 or in decimal form it's 0.006

4 0
3 years ago
A relationship between a producer and consumer is best illustrated by
makvit [3.9K]

Answer:

A zebra eating grass

Step-by-step explanation:

Its a zebra eating grass because the zebra in consuming grass, which grass is a producer.

6 0
3 years ago
Read 2 more answers
An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
Tanya [424]

Answer:

98%  Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size n_1 = 71

Sample size n_2 = 31

Sample mean \overline x_1 = 41628

Sample mean x_2 = 36,379

Population standard deviation \sigma_1 = 4934

Population standard deviation \sigma_2 = 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at z_{0.02/2} = 2.33

The Margin of Error = z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }

= 2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }

= 2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }

= 2.33 \times \sqrt{906504.06 }

= 2218.40

The Lower limit = ( \overline x_1 - \overline x_2) - (Margin \ of \ error)

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = ( \overline x_1 - \overline x_2) + (Margin \ of \ error)

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴  98%  Confidencce Interval is ( 3030.6, 7467.4 )

5 0
3 years ago
Other questions:
  • Please select the best answer thanks
    5·1 answer
  • How do i solve this? i need help
    14·1 answer
  • Please answer.
    11·2 answers
  • What’s the answer to this
    7·1 answer
  • If 375 miles in 5 hours how many miles per hour
    15·2 answers
  • Where would 4 cups be placed on the number line
    9·2 answers
  • Solve the following equation with the initial conditions. x¨ + 4 ˙x + 53x = 15 , x(0) = 8, x˙ = −19
    13·1 answer
  • An underwater canyon begins at 40 feet
    5·1 answer
  • a caterer charges $120 fo cater 15 people and $200 for 25 people. Write an equation in slope-intercept form to model thus situat
    7·1 answer
  • The lengths of adjacent sides of a rectangle are 572 units and 8,2
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!