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2 years ago

15

Thirty four times five

2 answers:

lara [203]2 years ago

7 0

170 is the answer to your question

likoan [24]2 years ago

5 0

Thirty four times five equals 170

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The radius of the large sphere is double the radius of the small sphere. How many times is the volume of the large sphere than t

kobusy [5.1K]

The volume of a sphere is $\cfrac{4}{3}\ \pi r^3$

So, if the small sphere has radius $r$ and the largest sphere has radius $2r$ , their volumes are

$V_1 = \cfrac{4}{3}\ \pi r^3,\quad V_2 = \cfrac{4}{3}\ \pi (2r)^3 = \cfrac{4}{3}\ \pi 8r^3$

So, their ratio is

$\cfrac{V_2}{V_1} = \cfrac{\frac{4}{3}\ \pi 8r^3}{\frac{4}{3}\ \pi r^3} = 8$

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3 years ago

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A school has 300 students. If the ratio of boys to girls is 31 to 44, how many girls are there in the school?

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176 girls

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31+44 = 75

300/75 = 4

4*44 = 176

176 girls in the school

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3 years ago

Which method do you prefer to use to find sums-count be tens and ones use compatible numbers or use friendly numbers and adjust?

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3 years ago

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12 out of 15 people in the US like to eat out. if 400 people selected eating out how many people took the survey?

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2 years ago

The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in

ryzh [129]

Answer:

Area of square pyramid is $153883.8\ m^{2}$ .

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is $154 \ m^{2}$ . The side of the square is $230 \ m$ and The height of each triangle is $187 \ m$ .

So, Area of Square shape = $154 \ m^{2}$

Side of square = $230 \ m$

Height of each triangle = $187 \ m$

Finding the Height of triangular shape which is here known as slant height.

In Δ ABO, applying Right angle pythagorean Theorem,

Base $(BO)$ = $\frac{230}{2} = 115\ m$

Height $(AO)$ = $187\ m$

Now,

∴ $AB^{2} = AO^{2} \ + \ BO^{2}$

⇒ $AB= \sqrt{AO^{2} \ + \ BO^{2} }$

⇒ $AB= \sqrt{187^{2} \ + \ 115^{2} }$

⇒ $AB= \sqrt{34969 \ + \ 13225 }$

⇒ $AB= 219.53 \ m$

Then,

Area of square pyramid = $area \ of \ square + \ 4\times area \ of \ traiangle$

= $side\times side + 4\times\frac{1}{2}\times AB\times Base$

= $230\times 230 \ + 2\times 219.53\times 230$

= $52900 + 100983.8$

= $153883.8 \ m^{2}$

Hence, Area of square pyramid is $153883.8\ m^{2}$ .

6 0

2 years ago