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2 years ago

What is a solutions of x^2-2x+10=0?

Mathematics

1 answer:

Debora [2.8K]2 years ago

8 0

Answer:

x = 1± 3i

Step-by-step explanation:

x^2-2x+10=0

We can complete the square to solve by subtracting 10 from each side

x^2-2x+10-10=-10

x^2 -2x = -10

We need to add (2/2) ^2 to each side or 1

x^2 -2x+1 = -10 +1

x^2 -2x+1 = -9

The left side factors into (x- (2/2) ) ^2

(x-1) ^2 = -9

Take the square root of each side

sqrt((x-1) ^2 =± sqrt(-9)

x-1 = ±sqrt(-1) sqrt(3)

Remember the sqrt(-1) = i

x-1 = ± 3i

Add 1 to each side

x-1+1 = 1± 3i

x = 1± 3i

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- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

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1. Plot the given points, as you can see in the graph attached.

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3 years ago

What is a solutions of x^2-2x+10=0?​

What is a solutions of x^2-2x+10=0?