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garik1379 [7]
2 years ago
5

What is a solutions of x^2-2x+10=0?​

Mathematics
1 answer:
Debora [2.8K]2 years ago
8 0

Answer:

x = 1± 3i

Step-by-step explanation:

x^2-2x+10=0

We can complete the square to solve by subtracting 10 from each side

x^2-2x+10-10=-10

x^2 -2x = -10

We need to add (2/2) ^2  to each side or 1

x^2 -2x+1 = -10 +1

x^2 -2x+1 = -9

The left side factors into (x- (2/2) ) ^2

(x-1) ^2 = -9

Take the square root of each side

sqrt((x-1) ^2 =± sqrt(-9)

x-1 = ±sqrt(-1) sqrt(3)

Remember the sqrt(-1) = i

x-1 = ± 3i

Add 1 to each side

x-1+1 = 1± 3i

x = 1± 3i

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Answer:

D

Step-by-step explanation:

We want to find:

(x^2+2x-3)(4x^2-5x+6)

Distribute:

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