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Zina [86]
3 years ago
5

What number has the prime factorization 2 6th * 5 6th show your work

Mathematics
1 answer:
velikii [3]3 years ago
6 0
The steps for calculating the prime factors of a number is similar to the process of finding the factors of any number.
Start dividing the number by the smallest prime number i.e., 2, followed by 3, 5, and so on to find the smallest prime factor of the number.
Again, divide the quotient by the smallest prime number
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Which inequalities are true? Check all that apply
leva [86]

Answer:

A , B, C, E

Step-by-step explanation:

√4 = 2

√5 = 2.24

√5.5 = 2.36

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<h3>A)</h3>

√5 < 2.3<√6

2.24 < 2.3 < 2.45 True

<h3>B)</h3>

√5 < 2.4<√6

2.24 < 2.4 < 2.45 True

<h3>C)</h3>

√4 < √5 < √5.5

2 < 2.24 < 2.36 True

<h3>D)</h3>

√8 < 3 < √9

2.83 < 3 < 3 False

<h3>E)</h3>

√8 < 2.9 < √9

2.83 < 2.9 < 3 True

<h3>F)</h3>

√4 < 4.5 < √5

2 < 4.5 < 2.24 False

3 0
3 years ago
Read 2 more answers
Please help! 15 points! Do not steal points or I will report! Explanation = Brainliest!
GuDViN [60]

(Answer is below)

Let's solve this step-by-step.

1. Prime factorization of 384.

=\sqrt{2^7\times3}

2. Apply the exponent rule. (Formula: a^b^+^c=a^b\times a^c)

=\sqrt{2^6\times2\times2\times3}

3. Apply the radical rule. (Formula: \sqrt{ab} =\sqrt{a}\sqrt{b} or a\geq 0,b\geq 0)

=\sqrt{2^6} \sqrt{2\times3}

3a. Solve 2 to the 6th power.

\sqrt{2\times2\times2\times2\times2\times2} =8

4. Multiply 2 by 3. (Note: Put the 8 in your final answer)

\sqrt{2\times3} =8\sqrt{6}

Your answer is: 8\sqrt{6}

Let me know if you have any questions.

~ Lily, from Brainly.

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