We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4
6 + 4 = 10
6*4 = 24
So we can break up the 10ab into 6ab+4ab and then use factor by grouping
a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
(a+4b)(a+6b)
Therefore, the original expression factors completely to (a+4b)(a+6b)
Answer:
1) the angles are congruent, or the same
2) the angles are complementary, or add up to 90 degrees
3) the angles add up to 180 degrees
4) the angle is a right angle
5) they are congruent
6) they are complementary angles, or add up to 90 degrees
7) they are supplementary angles, or add up to 180 degrees
8) angle 1 is congruent to angle 4
9) angle K is supplementary to angle L
Step-by-step explanation:
8 and 9 are transitivity
The other statements correspond with the sentence starters.
Answer:
The statement is true.
Step-by-step explanation:
Given the statement we have to tell the statement is true or false.
The statement is
"The circumcenter of a triangle is the center of the only circle that can be circumscribed about it"
The circumcenter of triangle is the point in the triangle where the perpendicular bisectors of sides intersect.
The center of the circumscribed circle is the the point where the perpendicular bisectors of the sides meet.
Hence,
The circumcenter is also center of the triangle's circumcircle - the circle that pass through all three of the triangle's vertices.
Therefore, the given statement is true.
Answer:
I = V/R
Step-by-step explanation:
V = IR
Divide by R on both the sides,
I = V/R
Answer:
Four
Step-by-step explanation:
The degree of a polynomial is the highest of the degree of the monomials with non-zero co-efficient. In this problem we are given the polynomial:
The degree of the polynomial is 4.
For a polynomial of <em>n- degree </em>we have <em>n solutions counting multiplicity</em>.
So for this four degree polynomial we would have 4 solutions. Could be real or complex depending on the equation.
