Even though the mass of the sun is much greater than the mass of the moon, the moon has a greater influence on the tides than the sun. This is because the sun is much farther away from the earth, so its tidal force is only about half that of the moon.
The answer to the problem is 14
Distance = Square Root ( (X difference)^2<span> + (Y difference)^</span>2<span> )
</span>
Distance = Square Root ( (-4 --7)^2 + ( 3 --2)^2<span> )
</span>Distance = Square Root (3^2 + 5^2)
<span>Distance = Square Root (9 + 25)
Distance = </span><span>Square Root (34)
Distance = </span><span>5.8309518948
Therefore the length of lm equals </span>
<span>
<span>
<span>
5.8309518948
</span>
</span>
</span>
Answer:
(f-g)(x) = - 3 x² + 3 x -6
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given function f(x) = x² + x - 5
g(x) = 4 x² - 2 x + 1
(f-g)(x) = f(x) - g(x)
= x² + x - 5 - (4 x² - 2 x + 1)
= x² - 4 x² + x + 2 x - 5 -1
= - 3 x² + 3 x -6
(f-g)(x) = - 3 x² + 3 x -6
The answer to the first is a^2
0.0277777778 but for a power idk
8^1
d^0
and if e = 2 then the answer is 0.5 but idk power
