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Hitman42 [59]
3 years ago
6

I need some help please !

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer: prob 8

Step-by-step explanation:

NNADVOKAT [17]3 years ago
5 0
8 because since both sides are the same the angles must be equal to one another so ur setup should be 75=8x+11 so x=8
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Can someone help me convert each of these into improper fractions?
mariarad [96]

Answer:

(\frac{6}{1})(\frac{11}{4}  )

(-\frac{10}{3})(-\frac{17}{5})

(-\frac{9}{2} )(\frac{26}{3} )

(\frac{11}{6})(-\frac{9}{1}  )

Step-by-step explanation:

I hope this help you

8 0
2 years ago
Which property would be useful in proving that the product of two rational numbers is ALWAYS rational? A) a b + c d = ad + bc bd
Mademuasel [1]

Answer:

C

Step-by-step explanation:

So we need to understand what is rational numbers?

Rational number which can be written under this form: \frac{x}{y} when x any are both integers and y\neq 0

The question here is : Which property would be useful in proving that the product of two rational numbers. In math, when we talk about the product of at least two number, it implies to the multiplication in the operation.

Here, only answer C: \frac{a}{b} *\frac{c}{d} = \frac{ac}{bd} with the condition b\neq 0 and    d \neq 0 and a, b, c and d are integers. Product of two integers is always an integer..

3 0
3 years ago
Read 2 more answers
Help pls will mark branliest !
Mnenie [13.5K]

Answer:

10 Numbers

Step-by-step explanation:

6 0
3 years ago
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For the figure shown on the right find M 1
katrin2010 [14]
I think that’s a brand of tape beacuse there’s duck tape, scotch tape, paint tape, washie tape etc

Hope this helps:)
3 0
3 years ago
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Laws Of Indicies<br>Can someone please help me with this?​
nasty-shy [4]

Answer:

See below

Step-by-step explanation:

1) :  {a}^{5}  {b}^{4}  {c}^{3}  \div  {a}^{2}  {b}^{3} c \\  \\  = {a}^{5 - 2}  {b}^{4 - 3}  {c}^{3 - 1}  \\  \\  = {a}^{3}  {b}^{1}  {c}^{2}  \\  \\ = {a}^{3}  {b}  {c}^{2}  \\  \\  \\2)\:  (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4}   \div ( {a}^{2}  \times 3a) \\  \\  = 5 {a}^{4}   \div (3 {a}^{2 + 1}  ) \\  \\  = 5 {a}^{4}   \div (3 {a}^{3}  ) \\  \\  =   \frac{5}{3}  {a}^{4 - 3}  \\  \\ =   \frac{5}{3}  {a} \\  \\  \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4}  }  \\  \\  =   \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} }   \\  \\  =   \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} }    \\  \\  =   \frac{  {a}^{5} }{ {a}^{7} }   \\  \\  =  {a}^{5 - 7}  \\  \\  =  {a}^{ - 2}  \\  \\  =  \frac{1}{{a}^{2} }  \\  \\

8 0
3 years ago
Read 2 more answers
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