Answer: $ 990
Step-by-step explanation:
Since, the total number players, n = 12,
The least amount got by one team, a= $ 220
Let there is a successive difference of d,
Thus, the given situation forms an AP,
In which sum of the AP, ![S_n= \frac{12}{2}[2\times 220 + (12-1)d]](https://tex.z-dn.net/?f=S_n%3D%20%5Cfrac%7B12%7D%7B2%7D%5B2%5Ctimes%20220%20%2B%20%2812-1%29d%5D)
But, According to the question,

⇒ ![\frac{12}{2}[2\times 220 + (12-1)d]=7260](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B2%7D%5B2%5Ctimes%20220%20%2B%20%2812-1%29d%5D%3D7260)
![6[440 + (11)d]=7260](https://tex.z-dn.net/?f=6%5B440%20%2B%20%2811%29d%5D%3D7260)



Thus, the successive difference, d = $ 70
⇒ The amount of first price,
