6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
The Correct option is -4
because every other terms result in value = 4, where's -4 is the only different one hence doesn't belongs yo other three
Answer:
Option A. A and D
Step-by-step explanation:
This answer because they are both right triangles and are near the same size
Hope this helps!
Answer:
Option A is correct
Step-by-step explanation:
Hope it is helpful....
Side = 12xy+1
Perimeter = 4(12xy+1)
Perimeter = 48xy + 4 (Answer B)