Answer:
1931.7N
Step-by-step explanation:
We are told in the question that :
An auto ( a car) weighs = 2500 pounds
It s inclined at n horizontal Ange of 10°
We are asked to find the force that would prevents it from rolling down the street.
Since the unit for Force = Newton or kgm/s²
Step 1
Convert Weight in pounds to kg
1 pound = 0.453592kg
2500 pounds =
2500 pounds × 0.453592kg
= 1133.981kg
Step 2
Find the force that would prevents it from rolling down the street.
Force = Mass × Acceleration due to gravity × sin θ
Acceleration due to gravity = 9.81m/s
Force = 1133.981kg × 9.81 × sin 10°
Force = 1931.7237321 N
Approximately = 1931.7N
Answer:
7/4,
Step-by-step explanation:
it cant be simplified
Answer:
There is no picture
Step-by-step explanation:
1) Jason: Shop A - 11 units; Shop B - 12 units. Sales increase at 17% per week. So, 11 + 12 = 23.
f(x) = 23(1.17)ˣ
2) Daniel: Element A temp - 44(1.13)ˣ ; Element B temp - 17(1.13)ˣ. How much temp of Element A be more than the temp of Element B.
f(x) = 44(1.13)ˣ - 17(1.13)ˣ = 27(1.13)ˣ
f(x) = 27(1.13)ˣ
3) Maggie: Tshirt price - $13. Charity donation - 270
f(x) = 13x - 270
4) Mr. Smith: Length of backyard - 30x + 29 ; Length of square patio - 13x + 6
Length not covered by the patio.
f(x) = (30x + 29) - (13x + 6) = 30x - 13x + 29 - 6 = 17x + 23
f(x) = 17x + 23