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3 years ago

15

After planting a seed, you notice that it produces 2 leaves in 10 days. If it doubles the number of leaves it has every 10 days,

how many leaves will the plant have in 60 days?

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

Your final answer is 64.

Here's why:

Leaves Days

2 10

4 20

8 30

16 40

32 50

64 60

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Write an equation for the following tile pattern.<br><br> Figure 2<br><br> Figure 3<br><br> Figure 4

oksano4ka [1.4K]

Answer:

The general equation following the pattern becomes is 7 + (n - 1)×2

Where, n = The figure number - 1

Step-by-step explanation:

The pattern in the question can be described as follows;

Figure 2 = (5 + 2) squares boxes = 7 squares boxes

Figure 3 = (5 + 2 + 2) squares boxes

Figure 4 = (5 + 2 + 2 + 2) squares boxes

Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;

7 + (n - 1)×2.

3 0

3 years ago

Slope=10,y-intercept = - 5

marin [14]

Answer:

the equation of the above is

y= 10x - 5

7 0

2 years ago

Finding a polynomial of a given degree with given zeros

galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

$x=4$

Subtract 4 from both sides

$\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}$

The first factor is (x - 4)

$\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}$

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

$f(x)=(x-4)(x-1+i)(x-1-i)$

We will multiply them to find f(x)

$\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}$

Multiply it by (x - 4)

$\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}$

The answer is

$f(x)=x^3-6x^2+10x-8$

5 0

1 year ago

Greeley [361]

Answer:

the answer is d e and fans f

6 0

3 years ago

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Which equation represent a relationship where y is a nonlinear function of x? Select all that apply

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the question is a beat confusing please make it simplify

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3 years ago