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Usimov [2.4K]
3 years ago
12

What is the function? 4th grade math

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0
First you should find the slope:
(23-21)/(3-1) = 1
Then the y-intercept:
21=1+b
b=20

The function is: y=x+20

Naddika [18.5K]3 years ago
6 0
You are adding 20 to the x value each time
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The cost of fencing a circular field at the rate of Rs.24 per metre is Rs. 5280.
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Answer:

radius = 35.03 m

Step-by-step explanation:

5280/24 = circumference = 220 m

220 /Pi = diameter = 70.06 m

70.06/2 = radius = 35.03 m

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I’ll give brainliest if correct
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a

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Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x + 1)(x - 3)(x - 4)
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Answer: 3

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Find seven ordered pairs to the equation y=8 - x2. <br><br> NEED IT ASAP PLEASE!!!
zalisa [80]

-3   |  9-8=1       | (-3, 1)

-2   | 4-8= -4      | (-2, -4)

-1   | 1-8=-7       | (-1, -7)

0.  | 0-8=-8       |  (0, -8)

1   | 1-8=-7       |  (1, -7)

4 0
3 years ago
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Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
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