Question

Reduce the fraction to lowest terms m^2/m^2-n^2

Answer 1

Answer:

$\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}$

Step-by-step explanation:

Factor $\bold{m^2-n^2}$

$\bold{\left(m+n\right)\left(m-n\right)}$

Rewrite Equation

$\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}$

Answer 2

Answer:

$\frac{m^2}{(m+n)(m-n)}$

Step-by-step explanation:

Here we have to simplify the denominator of the expression given in the question.

We will use the formula for

Difference of the squares which us given as under

$a^2-b^2=(a+b)(a-b)$

Let us now simplify the denominator

$m^2-n^2=(m+n)(m-n)$

Hence

Our answer is

$\frac{m^2}{(m+n)(m-n)}$