All categories

3 years ago

PLEASE HELP ASAP!!(SHOW ALL STEPS) Determine the factors x2y + 3x2 + 3y + 9

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

Answer:

(y+3) (x^2+3)

Step-by-step explanation:

x^2y + 3x^2 + 3y + 9

I will factor by grouping

Taking the first two terms I can factor out x^2

Taking the last two terms I can factor out 3

x^2y + 3x^2 + 3y + 9

x^2(y+3) + 3(y+3)

Now I can factor out (y+3)

(y+3) (x^2+3)

Since(x^2+3) and (y+3) cannot be factored , this is completely factored

Mars2501 [29]3 years ago

6 0

Answer:

(y+3) (x^2+3)

x^2y + 3x^2 + 3y + 9

<u>grouping</u>

x^2y + 3x^2 + 3y + 9

x^2(y+3) + 3(y+3)

(y+3) (x^2+3)

You might be interested in

Which expression models the following<br> phrase: "an hourly wage of $12.75"?

inessss [21]

Answer:

h = number of hours worked

m = total wage of worked hours

12.75h = m

8 0

3 years ago

Sneha went to a park 150m long and 80m wide. She took one complete round on its boundary. What is the distance covered by Sneha?

Blababa [14]

Answer:

460 m

Step-by-step explanation:

Boundary = perimeter

Perimeter = 2(length + width)

= 2(150 + 80)

= 2(230)

= 460 m

7 0

1 year ago

Read 2 more answers

Please help me, I am not sure of the answer.

coldgirl [10]

I think it’s b not sure tho

6 0

2 years ago

Which of the following types of graphs is best for plotting the mean, median, and mode of data?

frutty [35]

Answer:

Stem-and-leaf. You can use a stem-and-leaf plot to find the mean, median and mode of a set of data.

5 0

2 years ago

A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take

muminat

Answer:

The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill (Du) = 2 miles

The time taken by jogger in downhill (Td) = T hour

The time taken by jogger in uphill (Tu) = T hour

Let The speed of jogger in uphills (Su) = x mph

So ,The speed of jogger in downhills (Sd) =( x + 6 ) mph

∵, Time = $\frac{Distance}{Speed}$

So, Tu = $\frac{Du}{Su}$

Or, T = $\frac{2}{x}$ h

And Td = $\frac{Dd}{Sd}$

Or, T = $\frac{5}{(x + 6)}$ h

∵ Time duration of both is same

∴ $\frac{2}{x}$ = $\frac{5}{(x + 6)}$

Or, 2 × (x + 6) = 5x

Or, 2x + 12 = 5x

So, 12 = 3x

∴ x = $\frac{12}{3}$ = 4 mph

And x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour Answer

5 0

3 years ago