Answer:
The bags would weigh 27lbs. multiply 4 1/2 and6 and you get 27lbs.
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
The lengths of the sides are 7, 23 and 24.
In order to find this, we need to add all of the side lengths together and set equa to 54. This will allow us to solve for n.
n + 3n + 2 + 4n - 4 = 52
8n - 2 = 52
8n = 54
n = 7
This gives us the length of the first side. To solve for the others, plug 7 into the equations.
3n + 2
3(7) + 2
21 + 2
23
Then the next one.
4n - 4
4(7) - 4
28 - 4
24
Answer:
6:05
Step-by-step explanation:
5:20+40= 6:00
6:00+5= 6:05