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Flura [38]
4 years ago
6

120 miles in 3 hours= ?unit rate

Mathematics
2 answers:
seraphim [82]4 years ago
6 0

Answer:

40 mph

40 miles in 1 hr

7nadin3 [17]4 years ago
4 0
D=rt
120= r(3)
120/3=3r/3
40=r
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how much would $600 invested at 8% interest compound continuously be worth after 3 years? round to the nearest cent a(t)=p.ert
Aleksandr-060686 [28]
Given:
$600 principal
8% rate = 8/100 = 0.08
3 years time

Solving for A:
A = P⋅e^rt
where:
A is the amount
P is the principal
e is the mathematical constant
r is the rate of interest
t is the time in years

A = P⋅e^rt
= 600⋅e^(0.08⋅3)
= 600(2.718281828459045)^(0.24)
A = $762.70

$600 compounded continuously at a rate of 8% for 3 years will yield a final amount of $762.70 

5 0
4 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their
ella [17]
The answer is 20

I hope it helps
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3 years ago
PLEASE HELP ME! asap please
Radda [10]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
0.9x-2.1+0.9=0.2(5-x)
VARVARA [1.3K]
.9x-2.1+.9=.2(5-x) multiply .2(5-x)
.9x-2.1+.9=1-.2x; add - 2.1 + .9
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7 0
4 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
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