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Lady bird [3.3K]
3 years ago
8

Please help! See attached image!

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

Step-by-step explanation:

The standard form of a quadratic equation is expressed as

Ax² + Bx + C = 0

The given quadratic equation is expressed as

2 = - x + x² - 4

The first step is to rearrange the given equation so that it will take the standard form. Therefore,

Subtracting 2 from the Left hand side and the right hand side of the equation, it becomes

2 - 2 = - x + x² - 4 - 2

- x + x² - 6 = 0

x² - x - 6 = 0

Comparing this equation with that of the standard form,

a = 1

b = - 1

c = - 6

Substituting into the quadratic formula, it becomes

x = (- b ±√b² - 4ac)/2a

x = (- - 1 ±√- 1² - 4 × 1 × -6)/2a × 1

x = ( 1 ±√1 + 24)/2

x = (1 + √25)/2 or x = (1 - √25)/2

x = 6/2 = 3 or x = - 4/2 = - 2

Sever21 [200]3 years ago
6 0

Answer:

x1=-2, x2=3

Step-by-step explanation:

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Julissa gave out an equal number of oranges to each of the 6 apartments on her floor. If she gave each apartment 5 oranges, how
dybincka [34]

Answer:

30 oranges

Step-by-step explanation:

Total number of apartment in julissa floor = 6

Number of oranges given to each apartment = 5

how many oranges did Julissa give out in all?

Total number of oranges julissa's gave out = Total number of apartment in julissa floor × Number of oranges given to each apartment

= 6 × 5

= 30 oranges

Therefore, total number of oranges julissa gave out = 30

4 0
3 years ago
Read 2 more answers
What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}
\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
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Answer:

Alex can drive 480miles in one day period.

Step-by-step explanation:

$162- $42 =$120

$120/0.25¢=480

480miles

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C

Step-by-step explanation:

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