Area of square base:
13 x 13 = 169
Area of triangular sides:
B x H/2
13 x 16/2 = 104
104 x 4 = because there are 4 triangular sides of the figure = 416
416 + 169 = 585in^2
590in^2
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
C (The lower left one)
Step-by-step explanation:
I saw that the vertex was equal to (-1,1) and that is the only answer that makes sense
Answer:
Hi how is your day going?
Step-by-step explanation:
I have some jokes and I hope you like them.
Knock Knock.
Who's There?
Scold.
Scold who?
Scold outside, let me in!
Knock Knock.
Who's there?
Tank.
Tank who?
You're Welcome!
