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Kryger [21]
3 years ago
9

15. please 10 points if you help me with this question

Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

No it does not stay the same

Original ratio is 6:5 which means it will only stay the same if the amount of movies to band is taken at multiples of this ratio. per sample if 24 movies are sold then

24/6=4 so you will have to multiply or sell 5*4=20 of the band ones to be able to keep same ratio.

You might be interested in
What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?
bezimeni [28]
3\equiv3\mod{20}
3^2\equiv9\mod{20}
3^3\equiv27\equiv7\mod{20}
3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}

7\equiv7\mod{20}
7^2\equiv49\equiv9\mod{20}
7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}
7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}

9\equiv9\mod{20}
9^2\equiv3^4\equiv1\mod{20}

11\equiv11\mod{20}
11^2\equiv121\equiv1\mod{20}

13\equiv-7\equiv13\mod{20}
13^2\equiv169\equiv9\mod{20}
13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}
13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}

17\equiv-3\equiv17\mod{20}
17^2\equiv(-3)^2\equiv9\mod{20}
17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}
17^4\equiv(-3)^4\equiv81\equiv1\mod{20}

19\equiv-1\equiv19\mod{20}
19^2\equiv19(-1)\equiv-19\equiv1\mod{20}

Generally speaking, a number x coprime to n will be a primitive root of n if we have x^n\equiv x\mod{n}, or x^{n-1}\equiv1\mod{n}. In other words, if x is of order n-1 modulo n, then x is a primitive root of n.

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.
6 0
4 years ago
I need help with an area math question
Ede4ka [16]

Answer:

Step-by-step explanation:

Area of outer triangle = \dfrac{4x*(4x+3)}{2}= 2x*(4x +3)

                                    = 2x*4x + 2x*3

                                   = 8x² + 6x

Area of inner triangle= \dfrac{2x*(2x+5)}{2}=x*(2x+5)=x*2x+x*5=2x^{2} + 5x

Area of aluminium = area of outer triangle - area of inner triangle

                        = 8x² + 6x + 2x² + 5x

                        = 10x² + 11x

Area of 20 aluminum borders = 20*(10x² + 11x)  = 200x² + 220x

b) x = 25 cm

Area of 20 aluminum borders = 200*25² + 220*25

                                                  = 200 * 625 + 220*25

                                                 = 125000  + 5500

                                                  = 130500 cm²

c) Area of inner triangle (Glass) = 5500 cm²

Cost of aluminium = 130500 * 0.06 = $ 7830

Cost of glass = 5500 * 0.03 = $ 165

Cost of making 20 windows =  7830 + 165 = $ 7995

7 0
3 years ago
Help please .............​
kow [346]
<h2>Answer: 88</h2><h2>Hope it helped!</h2>
7 0
3 years ago
The school has a $500 budget for pizza. Pizza costs $15 per pie and the school orders 27 of them. How much money will be left in
Fynjy0 [20]

Step-by-step explanation:

27×15=405 which means there is 95$ left

3 0
3 years ago
A pet store has 7 tanks of fish. Each tank has k fish. Using k, write an expression for the total number of fish in the store.
MrMuchimi
7=k +k = 7k that the correct answer
3 0
4 years ago
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