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3 years ago

Write the standard equation of a circle with center $\left(-3,\ 4\right)$ and radius $1$ .

Mathematics

1 answer:

Nostrana [21]3 years ago

6 0

Answer:

(x + 3)² + (y – 4)² = 1

Step-by-step explanation:

(x – h)² + (y – k)² = r².

Where (h, k) is the center of the circle, and r is the radius of the circle.

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0 = −5n − 2n How do I solve this

masha68 [24]

Combine like terms and then divide out the coefficient to solve for n

8 0

2 years ago

Help me pleaseeee :) for brainliest answer

kifflom [539]

Answer:

2:14, 1:7, 3:21, and 18:126

Step-by-step explanation:

They are all multiplying by 7.

2*7= 14

1*7= 7

3*7= 21

18*7= 126

Hope this helps! :)

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2 years ago

You are ima room with other students and are asked to get in groups of 3. When finished, there are 21 groups of 3. How manny stu

ivolga24 [154]

There are 63 students in the room, this is because 21 time 3 gives you 63.

6 0

2 years ago

Read 2 more answers

What is the 5th equivalent fraction to <br> 1<br> 8<br> ?

valkas [14]

Answer:

5/40

Step-by-step explanation:

1/8 = 2/16 = 3/24 = 4/32 = 5/40

you just need to add 1 to the numerator(number on top) and 8 to the denominator(number at bottom). :)

7 0

2 years ago

Solve for x in the equation x squared + 2 x + 1 = 17.

Papessa [141]

Answer:

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

Step-by-step explanation:

given equation

$x^2 +2x +1 = 17$

subtracting 17 from both sides

$x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\$

the solution for quadratic equation

$ax^2 + bx + c = 0$ is given by

x = $x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a$

________________________________

in our problem

a = 1

b = 2

c = -16

$x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4 + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x = ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\$

thus value of x is

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

3 0

2 years ago