The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
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As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
Answer:
14π
Step-by-step explanation:
Area πr^2= 49π sq cm
so r= 7 cm
perimeter= 2πr= 14π
sin ( 300 ) −4 cot(−45) csc(60)
Answer:
y=1/6x+3
the slope has to be negative reciprocal and it passes though (6,4)
Answer:
The value of the y-coordinate is -2
Step-by-step explanation:
Here in this question, we want to use the section formula to determine the y- coordinates of the line that divides the segment in the ratio 1:3 or 1/3
The formula to use to get the coordinates is;
( (mx2 + nx1) /m + n , (my2 + ny1)/( m + n))
So in this case;
m = 1 n = 3
x1 = 4 , x2 = 5
y1 = -2 , y2 = -2
So substituting these values ( we will only make for the y part since we only need to get the y coordinate)
Hence;
[1(-2) + 3(-2)]/(1+3) = (-2-6)/4 = -8/4 = -2