No, there is not a product rule for integration.
To integrate (2x - 1)(6x + 5), start expanding the product:
(2x - 1)(6x + 5) = 12x^2 + 10x - 6x - 5 = 12x^2 + 4x - 5.
Now, I guess you know how to integrate that:
∫ (12x^2 + 4x - 5) dx = ∫12x^2 dx + ∫4x dx + ∫ (-5) dx = 4x^3 + 2x^2 - 5x + C
Answer:
8,9,10
Step-by-step explanation:
Let x-1, x and x+1 be the consecutive integers
(x-1)(x+1) = 5x + 35
x² - 1 - 5x - 35 = 0
x² - 5x - 36 = 0
x² - 9x + 4x - 36= 0
x(x - 9) + 4(x - 9) = 0
(x - 9)(x + 4) = 0
x = 9, -4
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hope this helped :)
Answer:
y = 2/3x
Step-by-step explanation:
