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lianna [129]
3 years ago
15

A box contains10 pens, 5 of the pens are red, 4 are balck and 1 are bluem What is the probability of pulling out a black pen fir

st, putting it back into the box, and then pulling a red pen ?
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0
Pulling out a black pen first will grant you a 40% chance of that occurring, then when you put it back the probability of you pulling out a red pen would be 50% so in decimal form these two values would be .40 and .50 multiply these two together you should get .20 or a 20% chance. Also a written fraction would be 1/5, all of which are valid answers.
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Geraldine is asked to explain the limits on the range of an exponential equation using the function f(x) = 2^x. She makes these
GalinKa [24]

<u>General Idea:</u>

Domain is the values of x which gives a defined output to the function, and Range is the values of y that we get by substituting domain values of x. For the function f(x) = a^x, where a > 0, the domain will be all real numbers and range will be all values greater than 0. That is the graph will be very close to x-axis but will never touch it.

<u>Applying the concept:</u>

From the attached table, we can notice that as x increases infinitely, the y-values are continually doubled for each single increase in x and as x decreases infinitely, the y-values are continually halved for each single decrease in x.

Option 1: "Statement 1 is incorrect because the y-values are increased by 2, not doubled".

Option 1 is INCORRECT because Statement 1 is TRUE & CORRECT.

Option 2: "Statement 2 is incorrect because the y-values are doubled, not halved".

Option 2 is INCORRECT because Statement 2 is TRUE & CORRECT.

Option 3: "The conclusion is incorrect because the range is limited to the set of the integers"

Option 3 is INCORRECT because, the range will be always greater than 0, because irrespective of how many times y is halved for each single decrease in x, the y will still be a positive fraction and won't be a negative.

Option 4: "The conclusion is incorrect because the range is limited to the set of positive real numbers"

<em><u>Option 4 is CORRECT because y value will be positive irrespective of whatever x we substitute in the function.</u></em>

8 0
3 years ago
Read 2 more answers
X+20≥-7 i need help pls lollllllllllllllllllllllllll
Zina [86]

Answer:

Step-by-step explanation:

x is greater or equal to 13

7 0
3 years ago
What is 11 Over 12+4 Over 9?
erastova [34]
11/16/9= is 11÷16÷9 which is approximately 0.076
3 0
3 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
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A customer placed an order with a bakery for cupcakes.
oksian1 [2.3K]

Answer:

is there more to this question because as it's it's it's just a statement

6 0
3 years ago
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