What is the length of the leg.s of the triangle below

Past experience at the Pasadena Travel Agency indicated that 44% of those persons who wanted the agency to plan a vacation for t

kap26 [50]

Answer: Yes. There there been a significant shift upward in the percentage of persons who want to go to Asia.

Step-by-step explanation:

From the information given in the question, past experience at the Pasadena Travel Agency shows that 44% of people who came to plan a vacation with the agency wanted to go to Asia.

During the most recent busy season, a sampling of 1,000 plans was selected at random from the files. It was found that 480 persons wanted to go to Asia on vacation. The percentage of people who want to go to Asia now will be:

= 480/1000 × 100

= 48%

Therefore, there has been a significant shift upward in the percentage of persons who want to go to Asia.

8 0

3 years ago

4 - 1 1/4 A. 3 1/4 B. 3 3/4 C. 2 3/4 D. 2 1/4

AleksAgata [21]

The answer to this question is c. 2 3/4

6 0

3 years ago

Read 2 more answers

_____ less than a number is 51

Kryger [21]

Answer:

W number - blank is 51.

Step-by-step explanation:

I don't understand what the question is. What is the number unless you want something random then here:

Blank - 52

a number = 1

52 - 1 = 51

3 0

3 years ago

To graduate this semester, you must pass Statistics 314; and you estimate that you have an 85% chance of passing. You need to pa

Nitella [24]

Answer:

Probability of graduating this semester is 0.7344

Step-by-step explanation:

Given the data in the question;

let A represent passing STAT-314

B represent passing at least in MATH-272 or MATH-444

M1 represent passing in MATH-272

M2 represent passing in MATH-444

C represent passing GERMAN-32

now

P( A ) = 0.85, P( C ) = 90, P( M1 ) = P( M2 ) = 0.8

P( B ) = P( pass at least one of either MATH-272 or MATH-444 ) = P( pass in MATH-272 but not MATH-444 ) + ( pass in MATH-444 but not in MATH 272) + P( pass both )

P( B ) = P( M1 ) × ( 1 - P( M2 ) ) + ( 1 - P( M1 ) ) × P( M2 ) + P( M1 ) × P( M2 )

we substitute

⇒ 0.8×0.2 + 0.2×0.8 + 0.8×0.8 = 0.16 + 0.16 + 0.64 = 0.96

∴ the probability of graduating this semester will be;

⇒ P( A ) × P( B ) × P( C )

we substitute

⇒ 0.85 × 0.96 × 90

⇒ 0.7344

Probability of graduating this semester is 0.7344

6 0

3 years ago

A researcher would like to determine whether a new tax on cigarettes has had any effect on people’s behavior. During the year be

sammy [17]

Answer:

a) $p_v =2*P(z$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the population mean is NOT significant different from 410 at 5% of significance.

b) $p_v =2*P(z$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is significant different from 410 at 5% of significance.

c) The expplanation why we have different outcomes is because for part a we use a higher standard error compared to part b. So we have enough evidence on part b to reject the null hypothesis that we no have significant difference from 410.

Step-by-step explanation:

1) Part a

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=386$ represent the sample mean

$\sigma=60$ represent the population standard deviation

n=9 represent the sample selected

$\alpha=0.05$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if we have significant difference on the mean, the system of hypothesis would be:

Null hypothesis: $\mu = 410$

Alternative hypothesis: $\mu \neq 410$

If we analyze the size for the sample is < 30 but we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{386-410}{\frac{60}{\sqrt{9}}}=-1.2$

P-value

Since is a two side test the p value would be:

$p_v =2*P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the population mean is NOT significant different from 410 at 5% of significance.

2) Part b

State the null and alternative hypotheses.

The system of hypothesis not changes:

Null hypothesis: $\mu = 410$

Alternative hypothesis: $\mu \neq 410$

Same statistic:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

But now the population deviation changes $\sigma=30$ . We can replace in formula (1) the info given like this:

$z=\frac{386-410}{\frac{30}{\sqrt{9}}}=-2.4$

P-value

Since is a two side test the p value would be:

$p_v =2*P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is significant different from 410 at 5% of significance.

7 0

3 years ago