This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3
Second part: when (6x + 2) is negative.
-(6x + 2) < 10 Divide both sides of inequality by -1 and change the sign.
(6x + 2) > -10
6x + 2 > -10
6x > -10 - 2
6x > -12 Divide both sides by 6.
x > -12/6
x > -2.
Combined solution: x < 4/3 and x > -2
-2 < x < 4/3.
Graph is a line on the number line between -2 and 4/3.
-2 and 4/3 are excluded from solution.
The amount of packing material is 1506 cubic inches
<h3>How to determine the amount of
packing material?</h3>
The given parameters are:
<u>Can</u>
Radius, r = 7 inches
Height, h = 18 inches
<u>Box</u>
Base dimension, l = 15 inches
Height, h = 19 inches
The volume of the can is:

So, we have:


The volume of the box is

So, we have:


The amount of packing material is;
Amount = V2 - V1
This gives
Amount = 4275 - 2769
Evaluate
Amount = 1506
Hence, the amount of packing material is 1506 cubic inches
Read more about volume at:
brainly.com/question/1972490
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Step-by-step explanation:
slope(m)=(Y-Y1)/X-X1
here,
M=1
(X1,Y1)=(11,3)
NOW,
m=(Y-Y1)/(X-X1)
1=(Y-3)/(X-11)
1×(X-11)=Y-3
X-11=Y-3
X-Y-11+3=0
X-Y-8=0
X-Y=0 is the required equation.