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harkovskaia [24]
3 years ago
6

A regular hexagon with side length 4 has the same area as a square. What is the length of the square?

Mathematics
1 answer:
svetlana [45]3 years ago
7 0

Answer: The length of the square is 6.44

Step-by-step explanation:

By definition, the area of a Regular polygon can be calculated with the following formula:

A=\frac{s^2n}{4tan(\frac{180}{n})}

Where "s" the length of any side of the polygon and "n" is the number of sides .

According to the information given in the exercise, you know that:

s=4

Since an hexagon has six sides, you know that:

n=6

Therefore, its area is:

A_h=\frac{(4^2)(6)}{4tan(\frac{180}{6})}\\\\A_h=24\sqrt{3}

The formula to find the area of a square is:

A=s^2

Where "s" is the length of any side of the square.

Since that regular hexagon has the same area as this square, you can substituting the area calculated above into the formula for calculate the area of a square, and then solve for "s".

Then you get:

24\sqrt{3}=s^2\\\\\sqrt{24\sqrt{3}}=s\\\\s=6.44

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See attachment for complete question

Required

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<em>Hence, Mieko is correct</em>

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Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
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Step-by-step explanation:

We have to prove both implications of the affirmation.

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We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

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melisa1 [442]

Answer:

C. g\,\circ \, f (x) =g(f(x))

Step-by-step explanation:

Let be f(x) = x-500000 the excedent on annual sales and g(x) = 0.2\cdot x the bonus factor, to determine the bonus amount a composition of f(x) is g(x) must be done. That is:

g\,\circ \, f (x) =g(f(x))

Hence, the right answer is C.

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