Well first we have to add 7/12 and 3/4 together which is 7/12+3/4=4/3. Now we have to reduce that to simplest form. Which would be 1 1/3 is 7/12+3/4 in simplest form!
1. a b c
2. a b c
3. a b c
4. a b c
5. a b c
then she eliminated 1 choice in 1 and 2, say as follows
1. b c
2. a b
3. a b c
4. a b c
5. a b c
Probability of answering correctly the first 2, and at least 2 or the remaining 3 is
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )
P(answering 1,2 and exactly 2 of 3.4.or 5.)=
P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong)
also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
so
P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18
note: P(1 correct)=1/2
P(2 correct)=1/2
P(3 correct)=1/3
P(4 correct)=1/3
P(5 wrong) = 2/3
P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108
Ans: P= 1/18+1/108=(6+1)/108=7/108
Answer:

Step-by-step explanation:
The diagram of the problem is drawn and attached.
Given that:



Also

Answer:
The answers are in solutions.
Step-by-step explanation:
- Four businessmen invested a sum of Rs. 250,000 in the ratio of 3:5:7:10 to start a new business.
(i) The amount invested by each businessman is;
<u>1^st businessman invested:</u>
<u />
Rs. 30,000
<u>2^nd businessman invested:</u>
<u />
<u />
= Rs. 50,000
<u>3^rd businessman invested:</u>
<u />
<u />
= Rs. 70,000
<u>4^th businessman invested:</u>
<u />
= Rs. 100,000
- If they gained Rs. 50,000
(ii) The profit each one of them got is;
<u>1^st businessman got:</u>
<u />
<u />
= Rs. 6,000
<u>2^nd businessman got:</u>
<u />
<u />
= Rs. 10,000
<u>3^rd businessman got:</u>
<u />
<u />
= Rs. 14,000
<u>4^th businessman got:</u>
= Rs. 20,000