$\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}$

$\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )$

5 0

2 years ago

Please help! Brainliest and 5 star given

goldfiish [28.3K]

Answer:

for second question

first length is 9cm

Area=l*b

= 9cm *9cm

=81<em><u>cm</u></em>

then, For semicircle

radius is 9 cm

area= 1/2*9cm

now , area of two semi circle = 2*1/2*9

= 9 cm

now area of shaded = 81-9

=72

5 0

3 years ago

Marcelo can select from 2 types of oranges and 3 types of peaches. If he randomly selects 1 orange and 1 peach, how many possibl

ICE Princess25 [194]

6

2x3=6

oranges-
peaches-

possible combination:
1-

2-

3-

4-

5-

6-

8 0

3 years ago